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Scheme

A

azuro

n00b
Joined
Dec 14, 2002
Messages
62
Here's the function
Code: 
(define not-divisible? 
   	(lambda (n)
   	... some code...
       ))

if I called the above function using:

Code: 
 (display ((not-divisible? 5) 10))

how do I get the value "10" within the function??

Thanks.
 
Well, one way is to add a second parameter to the lambda inside of not-divisible? If you have to use that exact template, you'll have to use curried lambda's.
 
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